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100% 1z1-071 Correct Answers - 1z1-071 Exam Braindumps

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Oracle 1z1-071 Exam Syllabus Topics:

TopicDetails
Topic 1
  • Managing Views: This domain covers how to manage or oversee modules.
Topic 2
  • Retrieving Data using the SQL SELECT Statement: This domain comprises topics such as using Column aliases, the SQL SELECT statement, utilizing the concatenation operator, literal character strings, alternative quote operator, and the DISTINCT keyword.
Topic 3
  • Using Subqueries to Solve Queries: In this module, topics include using Single Row Subqueries, Multiple Row Subqueries, and how to delete and update rows.
Topic 4
  • Managing Data in Different Time Zones: In this domain, topics include working with CURRENT_DATE, CURRENT_TIMESTAMP, and LOCALTIMESTAMP, and working with INTERVAL data types.
Topic 5
  • Restricting and Sorting Data: This domain covers topics such as applying Rules of precedence for operators in an expression, limiting Rows Returned in a SQL Statement, and utilizing Substitution Variables.
Topic 6
  • Using SET Operators: In this domain, the topics covered match the SELECT statements, utilizing the ORDER BY clause in set operations, the INTERSECT operator, and the MINUS operator.
Topic 7
  • Managing Objects with Data Dictionary Views: This domain covers utilizing data dictionary views.
Topic 8
  • Managing Indexes Synonyms and Sequences: In this domain, exam-takers are tested for their skill in managing Indexes, Synonyms, and Sequences.

Oracle Database SQL Sample Questions (Q285-Q290):

NEW QUESTION # 285
View the Exhibit and examine the structure in the DEPARTMENTS tables. (Choose two.)

Examine this SQL statement:
SELECT department_id "DEPT_ID", department_name, 'b' FROM
departments
WHERE departments_id=90
UNION
SELECT department_id, department_name DEPT_NAME, 'a' FROM
departments
WHERE department_id=10
Which two ORDER BY clauses can be used to sort the output?

  • A. ORDER BY DEPT_ID;
  • B. ORDER BY DEPT_NAME;
  • C. ORDER BY 3;
  • D. ORDER BY 'b';

Answer: A,C

Explanation:
Explanation/Reference:


NEW QUESTION # 286
Examine these statements:

Which two are true?

  • A. The MGR column In the DEPT table will not be able to contain null values.
  • B. The DEPT_FKEY constraint definition must be removed from the CREATE TABLE DEPT statement. and the added with an D. ALTER statement once both tables are created, for the two CREATE TABLE statements to execute successfully in the order shown.
  • C. The create TABLE EMP statement must precede the create table DEPT statement for all three statements to execute successfully.
  • D. Both foreign key constraint definition must be removed from the CREATE statements, and be added with ALTER TABLE statements once both tables are created, for the two CREATE TABLE statements to execute successfully in the order shown.
  • E. The DEPTNO column in the EMP table will be able to contain null values.
  • F. All three statements execute successfully in the order shown.

Answer: B,E


NEW QUESTION # 287
View the exhibit and examine the structure of the EMPLOYEES table.

You want to select all employees having 100 as their MANAGER_ID manages and their manager.
You want the output in two columns: the first column should have the employee's manager's LAST_NAME and the second column should have the employee's LAST_NAME.
Which SQL statement would you execute?

  • A. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON e.employee_id = m.manager_idWHERE m.manager_id=100;
  • B. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE e.manager_id=100;
  • C. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eWHERE m.employee_id = e.manager_id AND e.manager_id=100
  • D. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE m.manager_id=100;

Answer: B


NEW QUESTION # 288
These are the steps for a correlated subquery, listed in random order:
* The WHERE clause of the outer query is evaluated.
* A candidate row is fetched from the table specified in the outer query.
* This is repeated for the subsequent rows of the table, until all the rows are processed.
* Rows are returned by the inner query, after being evaluated with the value from the candidate row in the outer query.
Which is the correct sequence in which the Oracle server evaluates a correlated subquery?

  • A. 2, 4, 1, 3
  • B. 2, 1, 4, 3
  • C. 4, 2, 1, 3
  • D. 4, 1, 2, 3

Answer: A

Explanation:
Explanation
References:
http://rajanimohanty.blogspot.co.uk/2014/01/correlated-subquery.html


NEW QUESTION # 289
What is true about non-equijoin statement performance?

  • A. The between condition always performs less well than using the >= and <= conditions.
  • B. The between condition always performs better than using the >= and <= conditions.
  • C. The Oracle join syntax performs better than the SQL: 1999 compliant ANSI join syntax.
  • D. Table aliases can improve performance.
  • E. The join syntax used makes no difference to performance.

Answer: E

Explanation:
Performance implications related to non-equijoin SQL statements in Oracle Database are often a topic of optimization:
C . The join syntax used makes no difference to performance: In Oracle Database, the performance of a query involving joins is typically more dependent on factors like the underlying data distribution, indexes, optimizer statistics, and system configuration rather than the syntax (ANSI vs Oracle traditional syntax). The optimizer in Oracle is sophisticated enough to interpret different syntactical expressions of joins and optimize them accordingly.
Reference:
Oracle Database Performance Tuning Guide 12c, which discusses the impact of different join syntaxes and how Oracle's optimizer handles them.


NEW QUESTION # 290
......

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